1 需求:
将List<String>转化为List<Integer>,
1 按顺序排序
2 获取List<Integer>中的最大值
2 代码实现:
import org.apache.commons.collections4.CollectionUtils;
import org.apache.commons.collections4.Transformer;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class TestUtils {
public static void main(String[] args) {
List<String> functionIdStrList = new ArrayList<>();
functionIdStrList.add("1");
functionIdStrList.add("14");
functionIdStrList.add("7");
functionIdStrList.add("11");
List<Integer> functionIdList = new ArrayList<>();
CollectionUtils.collect(functionIdStrList, new Transformer() {
@Override
public Object transform(Object o) {
return Integer.valueOf(o.toString());
}
}, functionIdList);
Collections.sort(functionIdList);
System.out.println(functionIdList);
Integer max = Collections.max(functionIdList);
System.out.println("最大值 = " + max);
}
}
结果如如下图:
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