linux如何输出当前时间,如何在linux下输出当前时间

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  • Post category:linux


用localtime可直接分解出年月日时分秒

QUOTE:

struct tm *ptm;

long ts;

int y,m,d,h,n,s;

ts = time(NULL);

ptm = localtime(&ts);

y = ptm->tm_year+1900; //年

m = ptm->tm_mon+1; //月

d = ptm->tm_mday; //日

h = ptm->tm_hour; //时

n = ptm->tm_min; //分

s = ptm->tm_sec; //秒

一个有趣的例子:

QUOTE:

#include

#include

#include

int main() {

while (1) {

time_t sec = time(NULL);

struct tm t = *localtime(&sec);

printf(“\x1b[2J”); /* clear screen and home cursor */

printf(“\x1b[31;40m”); /* red foreground, black background */

printf(“\x1b[11;29H”); /* moves cursor to line 11, column 29 */

printf(“+—–^–^—–+\n”);

printf(“\x1b[12;29H”);

printf(“|\t%02d:%02d:%02d: |\n”, t.tm_hour, t.tm_min, t.tm_sec);

printf(“\x1b[13;29H”);

printf(“+——-V——+\n”);

sleep(1);

}

return 0;

}