SQLServer中将查询结果转换为Json格式应用分享

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SQLServer中将查询结果转换为Json格式应用分享

)

首先,创建存储过程,代码如下:

SET ANSI_NULLS ON

GO

SET QUOTED_IDENTIFIER ON

GO

CREATE PROCEDURE[dbo].[SerializeJSON](

@ParameterSQL AS VARCHAR(MAX)

)

AS

BEGIN

DECLARE @SQL NVARCHAR(MAX)

DECLARE @XMLString VARCHAR(MAX)

DECLARE @XML XML

DECLARE @Paramlist NVARCHAR(1000)

SET @Paramlist = N’@XML XML OUTPUT’

SET @SQL = ‘WITH PrepareTable (XMLString)’

SET @SQL = @SQL + ‘AS(’

SET @SQL = @SQL + @ParameterSQL+ ‘FOR XML RAW,TYPE,ELEMENTS’

SET @SQL = @SQL + ‘)’

SET @SQL = @SQL + ‘SELECT @XML=[XMLString]FROM[PrepareTable]’

EXEC sp_executesql @SQL, @Paramlist, @XML=@XML OUTPUT

SET @XMLString=CAST(@XML AS VARCHAR(MAX))

DECLARE @JSON VARCHAR(MAX)

DECLARE @Row VARCHAR(MAX)

DECLARE @RowStart INT

DECLARE @RowEnd INT

DECLARE @FieldStart INT

DECLARE @FieldEnd INT

DECLARE @KEY VARCHAR(MAX)

DECLARE @Value VARCHAR(MAX)

DECLARE @StartRoot VARCHAR(100);SET @StartRoot=’’

DECLARE @EndRoot VARCHAR(100);SET @EndRoot=’’

DECLARE @StartField VARCHAR(100);SET @StartField=’<’

DECLARE @EndField VARCHAR(100);SET @EndField=’>’

SET @RowStart=CharIndex(@StartRoot,@XMLString,0)

SET @JSON=’’

WHILE @RowStart>0

BEGIN

SET @RowStart=@RowStart+Len(@StartRoot)

SET @RowEnd=CharIndex(@EndRoot,@XMLString,@RowStart)

SET @Row=SubString(@XMLString,@RowStart,@RowEnd-@RowStart)

SET @JSON=@JSON+’{’

-- for each row
SET @FieldStart=CharIndex(@StartField,@Row,0)
WHILE @FieldStart>0
BEGIN
    -- parse node key
    SET @FieldStart=@FieldStart+Len(@StartField)
    SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
    SET @KEY=SubString(@Row,@FieldStart,@FieldEnd-@FieldStart)
    SET @JSON=@JSON+'"'+@KEY+'":'
    -- parse node value
    SET @FieldStart=@FieldEnd+1
    SET @FieldEnd=CharIndex('</',@Row,@FieldStart)
    SET @Value=SubString(@Row,@FieldStart,@FieldEnd-@FieldStart)
    SET @JSON=@JSON+'"'+@Value+'",'

    SET @FieldStart=@FieldStart+Len(@StartField)
    SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
    SET @FieldStart=CharIndex(@StartField,@Row,@FieldEnd)
END   
IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))
SET @JSON=@JSON+'},'
--/ for each row

SET @RowStart=CharIndex(@StartRoot,@XMLString,@RowEnd)

END

IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))

SET @JSON=’[’+@JSON+’]’

SELECT @JSON

END

GO

使用时方法如下

EXEC [SerializeJSON] ‘SELECT * FROM [TableName]’

输出的就是JSON格式的