翻转单词文本 c语言,编程算法 – 翻转单词顺序 代码(C)

  • Post author:
  • Post category:其他

翻转单词顺序 代码(C)

本文地址: http://blog.csdn.net/caroline_wendy

题目: 输入一个英文句子, 翻转句子中单词的顺序, 但单词内字符的顺序不变.

首先翻转(reverse)整个句子, 然后查找空格, 如遇到空格, 则翻转前面的单词, 或遇到结束符, 相同进行翻转.

代码:

/*

* main.cpp

*

* Created on: 2014.9.19

* Author: spike

*/

#include

#include

#include

#include

using namespace std;

void Reverse(char* begin, char* end) {

if (begin == NULL || end == NULL)

return;

while(begin < end) {

char tmp = *begin;

*begin++ = *end;

*end– = tmp;

}

}

char* ReverseWords(char* data) {

if (data == NULL) return NULL;

int len = strlen(data);

char* begin = data;

char* end = &data[len-1];

Reverse(begin, end);

begin = end = data;

while(*begin != ‘\0’) {

if (*begin == ‘ ‘) {

begin++;

end++;

} else if (*end == ‘ ‘ || *end == ‘\0’) {

Reverse(begin, –end);

begin = ++end;

} else {

++end;

}

}

return data;

}

int main(void)

{

char data[] = “I am Spike.”;

char* res = ReverseWords(data);

cout << res << endl;

return 0;

}

输出:Spike. am I

0a034eac14269d2139724a6bbf7f7310.png