我有一个包含按钮(链接)的视图文件：
在这个视图的其他地方,我还在一个包含我的userid和vacancyid的表单中声明了一些隐藏字段.
echo form_input(dataHiddenArray(‘userid’, $this->auth_user_id));
echo form_input(dataHiddenArray(‘vacancyid’, $vacancydetails[0]->vacancy_id));
这些隐藏字段转换为：
现在我希望能够将这些值发送到我的控制器(通过AJAX),以便我可以将它们插入到我的数据库中.
我的JS文件如下所示：
$(function() {
var postData = {
“userid” : $(“input.userid”).val(),
“vacancyid” : $(“input.vacancyid”).val()
};
btnSave = $(‘#savebutton’),
ajaxOptions = {
cache: false,
type: ‘POST’,
url: “<?php echo base_url();?>dashboard/vacancy/saveVacancy”,
contentType: ‘application/json’,
dataType: ‘text’
};
btnSave.click(function (ev) {
var options = $.extend({}, ajaxOptions, {
//data : $(this).closest(‘form’).serialize()
data: postData
});
ev.preventDefault();
// ajax done & fail
$.ajax(options).done(function(data) {
alert(data); // plausible [Object object]
//alert(data[0]); // plausible data
console.log(data); // debug as an object
}).fail(function (xhr, status, error) {
console.warn(xhr);
console.warn(status);
console.warn(error);
});
});
我的控制器看起来像这样(它没有做太多,因为它不返回任何东西)：
public function saveVacancy() {
//$this->load->model(‘user/usersavedvacancies_model’);
/*$data = array(
‘userid’ => $this->input->post(‘userid’),
‘vacancyid’=>$this->input->post(‘vacancyid’)
);*/
echo $this->input->post(‘userid’);
}
解决方法:
对javascript的微小更改
$(function () {
var postData = {
“userid”: $(“input.userid”).val(),
“vacancyid”: $(“input.vacancyid”).val()
};
btnSave = $(‘#savebutton’),
ajaxOptions = {
type: ‘POST’,
url: “<?php echo base_url(‘dashboard/vacancy/saveVacancy);?>”,
dataType: ‘json’
};
btnSave.click(function (ev) {
var options = $.extend({}, ajaxOptions, {
//data : $(this).closest(‘form’).serialize()
data: postData
});
ev.preventDefault();
// ajax done & fail
$.ajax(options).done(function (data) {
console.log(data); // debug as an object
if (data.result === ‘success’) {
alert(“Yeah, it saved userid ” + data.userid + ” to vacancy id ” + data.vacancyid);
}
}).fail(function (xhr, status, error) {
console.warn(xhr);
console.warn(status);
console.warn(error);
});
});
});
在控制器中
public function saveVacancy()
{
//assigning a more useable object name to the model during load
$this->load->model(‘user/usersavedvacancies_model’, ‘save_vacancy’);
$data = array(
‘userid’ => $this->input->post(‘userid’),
‘vacancyid’ => $this->input->post(‘vacancyid’)
);
//send data to model and model returns true or false for success or failure
$saved = $this->save_vacancy->doSaveId($data); //yes, I made up the method, change it
$result = $saved ? “success” : “failed”;
echo json_encode(array(‘result’ => $result, ‘userid’ => $data[‘userid’], ‘vacancyid’ => $data[‘vacancyid’]));
}
标签：jquery,php,javascript,ajax,codeigniter
来源： https://codeday.me/bug/20190627/1310071.html