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题目：给你一个由点组成的网格，再给一些连结相邻点的操作（横向、纵向），统计里面的正方形。

分析：模拟。直接用两个数组，记录横线和竖线，统计时枚举顶点扫描即可。

说明：先输出小的╮(╯▽╰)╭。

#include <algorithm>
#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>
#include <cmath>

using namespace std;

int H[10][10];
int V[10][10];

int main()
{
	int  n,m,x,y,T = 0;
	char c;
	while (~scanf("%d%d",&n,&m)) {
		getchar();
		for (int i = 1 ; i <= n ; ++ i)
		for (int j = 1 ; j <= n ; ++ j)
			V[i][j] = H[i][j] = 0;
		for (int i = 1 ; i <= m ; ++ i) {
			scanf("%c%d%d",&c,&x,&y);
			getchar();
			if (c == 'H')
				H[x][y] = 1;
			else 
				V[y][x] = 1;
		}
		if (T ++) printf("\n**********************************\n\n");
		printf("Problem #%d\n\n",T);
		
		int sum = 0;
		for (int l = 1 ; l <= n ; ++ l) {
			int count = 0,flag = 0;
			for (int i = 1 ; i+l <= n ; ++ i)
			for (int j = 1 ; j+l <= n ; ++ j) {
				flag = 1;
				for (int h = j ; h < j+l ; ++ h)
					if (!H[i][h] || !H[i+l][h]) flag = 0;
				for (int v = i ; v < i+l ; ++ v)
					if (!V[v][j] || !V[v][j+l]) flag = 0;
				count += flag;
			}
			sum += count;
			if (count) printf("%d square (s) of size %d\n",count,l);
		}
			
		if (!sum) printf("No completed squares can be found.\n");
	} 
    return 0;
}