jqeury ajax return,javascript – jQuery ajax return value – Stack Overflow

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How can I return the value “pinNumber” from jquery ajax so I can append it outside of the ajax. Here is my code

var x = pinLast + 1;

for(i=x;i<=pinMany;i++) {

var i = x++;

var cardNumber = i.toPrecision(8).split(‘.’).reverse().join(”);

var pinNumber = ”;

jQuery.ajax({

type: “POST”,

url: “data.php”,

data: “request_type=generator”,

async: false,

success: function(msg){

var pinNumber = msg;

return pinNumber;

//pin number should return

}

});

jQuery(‘.pin_generated_table’).append(cardNumber+’ = ‘+pinNumber+’

‘);

// the variable pinNumber should be able to go here

}

Please ask me if you don’t understand.. ^^ thanks