点在圆内吗?
时间限制: 1 Sec 内存限制: 128 MB
题目描述
定义一个Point类和Circle类，用于判断给定的一系列的点是否在给定的圆内。
其中，Point类：
1.有2个成员x和y，分别为其横坐标和纵坐标；1个静态成员numOfPoints，用于计算生成的点的个数。
2.具有构造函数、析构函数和拷贝构造函数，具体格式输出根据样例自行判断。
3. 具有静态方法int getNumOfPoints()，用于返回numOfPoints的值。
4. 具有int getX()和int getY()方法，用于获取横坐标和纵坐标。
Circle类：
1.拥有Point类的对象center，表示圆心坐标。拥有radius对象，表示圆的半径；1个静态成员numOfCircles，用于指示生成了多少个圆对象。
5. 具有构造函数、析构函数和拷贝构造函数，具体格式根据样例自行判断。
3.具有静态方法int getNumOfCircles()，返回numOfCircles的值。
6. 具有getCenter()方法，返回圆心坐标。注意：根据输出结果判断返回值类型。
7. 具有bool pointInCircle(Point &)方法，用于判断给定的点是否在当前圆内。是则返回true，否则返回false。
输入
输入分多行。
第一行M>0，表示有M个测试用例。
每个测试用例又包括多行。第1行包含3个整数，分别为一个圆的横坐标、纵坐标和半径。第2行N>0，表示之后又N个点，每个点占一行，分别为其横坐标和纵坐标。
所有输入均为整数，且在int类型范围内。
输出
输出见样例。注意：在圆的边上的点，不在圆内。
样例输入
2
0 0 10
3
2 2
11 11
10 0
1 1 20
3
2 2
1 1
100 100
样例输出
The Point (0, 0) is created! Now, we have 1 points.
The Point (1, 1) is created! Now, we have 2 points.
A circle at (1, 1) and radius 1 is created! Now, we have 1 circles.
We have 2 points and 1 circles now.
The Point (0, 0) is created! Now, we have 3 points.
A Point (0, 0) is copied! Now, we have 4 points.
A Point (0, 0) is copied! Now, we have 5 points.
A circle at (0, 0) and radius 10 is created! Now, we have 2 circles.
A Point (0, 0) is erased! Now, we have 4 points.
The Point (2, 2) is created! Now, we have 5 points.
(2, 2) is in the circle at (0, 0).
The Point (11, 11) is created! Now, we have 6 points.
(11, 11) is not in the circle at (0, 0).
The Point (10, 0) is created! Now, we have 7 points.
(10, 0) is not in the circle at (0, 0).
A Point (0, 0) is erased! Now, we have 6 points.
A circle at (0, 0) and radius 10 is erased! Now, we have 1 circles.
A Point (0, 0) is erased! Now, we have 5 points.
The Point (1, 1) is created! Now, we have 6 points.
A Point (1, 1) is copied! Now, we have 7 points.
A Point (1, 1) is copied! Now, we have 8 points.
A circle at (1, 1) and radius 20 is created! Now, we have 2 circles.
A Point (1, 1) is erased! Now, we have 7 points.
The Point (2, 2) is created! Now, we have 8 points.
(2, 2) is in the circle at (1, 1).
The Point (1, 1) is created! Now, we have 9 points.
(1, 1) is in the circle at (1, 1).
The Point (100, 100) is created! Now, we have 10 points.
(100, 100) is not in the circle at (1, 1).
A Point (1, 1) is erased! Now, we have 9 points.
A circle at (1, 1) and radius 20 is erased! Now, we have 1 circles.
A Point (1, 1) is erased! Now, we have 8 points.
We have 8 points, and 1 circles.
A circle at (1, 1) and radius 1 is erased! Now, we have 0 circles.
A Point (1, 1) is erased! Now, we have 7 points.
A Point (0, 0) is erased! Now, we have 6 points.
Append Code
int main()
{
int cases,num;
int x, y, r, px, py;
Point aPoint(0,0), *bPoint;
Circle aCircle(1,1,1);
cin>>cases;
cout<<"We have "<<Point::getNumOfPoints()<<" points and "<<Circle::getNumOfCircles()<<" circles now."<<endl;
for (int i = 0; i < cases; i++)
{
cin>>x>>y>>r;
bPoint = new Point(x,y);
Circle circle(*bPoint, r);
cin>>num;
for (int j = 0; j < num; j++)
{
cin>>px>>py;
if (circle.pointInCircle(*(new Point(px, py))))
{
cout<<"("<<px<<", "<<py<<") is in the circle at (";
cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
}
else
{
cout<<"("<<px<<", "<<py<<") is not in the circle at (";
cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
}
}
delete bPoint;
}
cout<<"We have "<<Point::getNumOfPoints()<<" points, and "<<Circle::getNumOfCircles()<<" circles."<<endl;
return 0;
}#include<iostream>
using namespace std;
class Point
{
private:
int x,y;
static int numofpoints;
public:
friend class Circle;
Point():x(0),y(0){numofpoints++;cout<<"The Point"<<" "<<'('<<x<<','<<" "<<y<<')'<<" "<<"is"<<" "<<"created!"<<" Now, we have "<<numofpoints<<" points."<<endl;}
Point(int xx,int yy):x(xx),y(yy){numofpoints++;cout<<"The Point"<<" "<<'('<<x<<','<<" "<<y<<')'<<" "<<"is"<<" "<<"created!"<<" Now, we have "<<numofpoints<<" points."<<endl;}
Point(const Point &q):x(q.x),y(q.y){numofpoints++;cout<<"A Point"<<" "<<'('<<x<<','<<" "<<y<<')'<<" "<<"is"<<" "<<"copied!"<<" Now, we have "<<numofpoints<<" points."<<endl;}
~Point(){numofpoints--;cout<<"A Point"<<" "<<'('<<x<<','<<" "<<y<<')'<<" "<<"is"<<" "<<"erased!"<<" Now, we have "<<numofpoints<<" points."<<endl;}
static int getNumOfPoints(){return numofpoints;}
int getX(){return x;}
int getY(){return y;}
};
class Circle
{
private:
Point center;
double radius;
static int numofcircles;
public:
friend class Point;
Circle(int x1,int y1,double r):center(x1,y1),radius(r){numofcircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numofcircles<<" circles."<<endl;}
Circle(Point cen,double r):center(cen),radius(r){numofcircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numofcircles<<" circles."<<endl;}
Circle(const Circle &q):center(q.center),radius(q.radius){numofcircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is copied! Now, we have "<<numofcircles<<" circles."<<endl;}
~Circle(){numofcircles--;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is erased! Now, we have "<<numofcircles<<" circles."<<endl;}
static int getNumOfCircles(){return numofcircles;}
Point &getCenter(){return center;}
bool pointInCircle(Point &q)
{ if((q.x)>(center.x-radius)&&(q.x)<(center.x+radius)&&(q.y)>(center.y-radius)&&(q.y)<(center.y+radius))
return true;
else
return false;
}
};
int Point::numofpoints=0;
int Circle::numofcircles=0;