博客

Problem Description:

Given an array of size

n

, find the majority element. The majority element is the element that appears

more than


⌊ n/2 ⌋

times.

You may assume that the array is non-empty and the majority element always exist in the array.

Example 1:

Input: [3,2,3]
Output: 3

Example 2:

Input: [2,2,1,1,1,2,2]
Output: 2

Analysis:

本题的思路也比较简单，因为队列中最多的元素的个数大于队列长度的一半，因此维护一个变量用来记录队列中多次出现的变量。

Code:

class Solution {
    public int majorityElement(int[] nums) {
        int prev = nums[0];
        int cnt = 1;
        for(int i = 1; i < nums.length; i++) {
            if(nums[i] != prev) {
                cnt--;
            } else if(nums[i] == prev) {
                cnt++;
            }
            if(cnt <= 0) {
                prev = nums[i];
                cnt = 1;
            }
        }
        return prev;
    }
}