Linux脚本练习之script083-nginx日志分析之查询某个IP的详细访问情况

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script083



题目

注:题目来源于

SHELL26 nginx日志分析4-查询某个IP的详细访问情况

假设 nginx 的日志我们存储在

nowcoder.txt

里,格式如下:

192.168.1.20 - - [21/Apr/2020:14:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [21/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [21/Apr/2020:21:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.23 - - [21/Apr/2020:22:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.24 - - [22/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [22/Apr/2020:15:26:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:08:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:09:20:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:10:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:10:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:14:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:15:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [23/Apr/2020:16:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.24 - - [23/Apr/2020:20:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [23/Apr/2020:20:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:22:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:23:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"

现在需要你查询

192.168.1.22

的详细访问情况,按访问频率降序排序。你的脚本应该输出:

4 /1/index.php
2 /3/index.php



脚本一

首先通过

grep

命令查找到 IP 地址是

192.168.1.22

的记录行;然后通过

awk

命令提取第七列,即访问路径;然后通过

sort

命令对其进行排序;排序后重复路径相邻,所以可以通过

uniq -c

命令统计去重后的每条路径的出现次数;再通过

sort

命令按照访问频率降序排列;最后通过

awk

命令调整第一列和第二列的出现顺序,让出现次数在第一列,路径在第二列。

grep "192.168.1.22" nowcoder.txt  | awk '{print $7}' | sort | uniq -c | sort -nr | awk '{print $1,$2}'



脚本二

直接通过

awk

命令来进行正则表达式匹配,查找第七列路径列。

awk '/192.168.1.22/{print $7}' nowcoder.txt | sort | uniq -c | sort -nr | awk '{print $1,$2}'



脚本三

利用了关联数组,将查找到的路径放进关联数组中,并统计其出现次数;再在

END{}

中打印关联数组中的路径和出现次数;最后使用

sort

命令降序排列。

awk '/192.168.1.22/{map[$7]++} END{for(k in map) print map[k],k}' nowcoder.txt | sort -nr



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