‘您必须记住，在将代码转换为浏览器端代码之前，会读取服务器端(PHP)代码。 JavaScript被浏览器操纵……
因此，一维地说，您无法将JavaScript传递给PHP。
…然而
使用Ajax，在您的情况下，我建议您使用JSON将JavaScript数据发送到PHP页面并将响应带回JavaScript方法。我认为这符合您的需求。如果你愿意，我可以提供一个简单的例子。
// – 以下示例：
JavaScript的：
//Ajax Method
function processAjax(queryString, processDiv, responseDiv) {
responseDiv.innerHTML = ”;
var myAjax;
try {
// Modern Browsers–>
myAjax =new XMLHttpRequest();
} catch (e) {
// antique ie browsers–>
try {
myAjax =new ActiveXObject(“Msxml2.XMLHTTP”);
} catch (e) {
try{
myAjax =new ActiveXObject(“Microsoft.XMLHTTP”);
} catch (e) {
// Something went wrong
document.getElementById(‘processDiv’).innerHTML=””;
alert(“Your browser malfunctioned! Please try again. Consider installing a modern browser if the problem persists.”);
return false;
}
}
}
myAjax.onreadystatechange = function() {
if (myAjax.readyState == 4) {
var ajaxResponse = myAjax.responseText;
responseDiv.innerHTML = ajaxResponse;
processDiv.innerHTML = “”;
//NOTE: HERE IS WHERE AJAX IS FINISHED, SO IF YOU WANT TO DO SOMETHING ELSE HERE YOU CAN!
//POST PROCESSING—–>
// IE: alert(‘I am finished processing now!’);
// or call another function:
// anotherFunction();
} else {
processDiv.innerHTML = ‘
‘;
}
}
myAjax.open(“GET”, queryString, true);
myAjax.send(null);
}
function sendStorage() {
var helloVar = ‘Hello, I am passed to PHP #1’;
var worldVar = ‘I am the second value passed to PHP!’;
var processId = ‘process_div’;
var resultId = ‘result_div’;
var queryString = ‘http://www.mysite.com/process.php?hello=’ + helloVar + ‘&world=’ + worldVar;
processAjax(queryString, processId, resultId);
}
现在有些HTML：
现在有一个process.php(注意：为安全起见，我强烈建议你不要在你的JAVASCRIPT中显示服务器端处理页面)
//init
$hello = ”;
$world = ”;
$errors = 0;
//set
//Security note: never trust a URL request.. you should clean all $_GET, $_REQUEST, AND $_POST with the PHP htmlspecialchars() method (take a look at php.net for that)
(isset($_GET[‘hello’])) ? $hello = $_GET[‘hello’] : $errors++;
(isset($_GET[‘world’])) ? $world = $_GET[‘world’] : $errors++;
//process
if($errors > 0) {
echo ‘Errors Detected! Missing querystring get data!’;
} else {
echo ‘
Hello received: ‘ . $hello . ‘
‘;
echo ‘
World received: ‘ . $world . ‘
‘;
//now we can process $hello and $world server side!
}
＆GT;
重要提示：您应该学习一些JSON和$ _POST请求，因为它们更安全，更快，您可以轻松地操作返回的数据。我建议查看像jquery这样的库来简化示例。
我没有测试过这段代码，但它应该可以运行..如果您有任何问题或者这不能回答您的问题，请告诉我。
很高兴帮忙！