文章目录
链表中倒数第k个节点
输入一个链表,输出该链表中倒数第k个节点。为了符合大多数人的习惯,本题从1开始计数,即链表的尾节点是倒数第1个节点。例如,一个链表有6个节点,从头节点开始,它们的值依次是1、2、3、4、5、6。这个链表的倒数第3个节点是值为4的节点。
示例:
给定一个链表: 1->2->3->4->5, 和 k = 2.
返回链表 4->5.
思路:快慢指针
package listNode;
class ListNode {
int val;
ListNode next;
ListNode(int x) {
val = x;
}
}
public class GetKthFromEnd {
public ListNode getKthFromEnd(ListNode head, int k) {
ListNode fast = head;
while(k > 0){
fast = fast.next;
k--;
}
ListNode slow = head;
while(fast != null){
fast = fast.next;
slow = slow.next;
}
return slow;
}
public static void main(String[] args) {
ListNode head = new ListNode(1);
head.next = new ListNode(2);
head.next.next = new ListNode(3);
head.next.next.next = new ListNode(4);
head.next.next.next.next = new ListNode(5);
int k = 5;
GetKthFromEnd test = new GetKthFromEnd();
ListNode res = test.getKthFromEnd(head,k);
while(res != null){
System.out.println(res.val + " ");
res = res.next;
}
}
}
从尾到头打印链表
输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。
示例 1:
输入:head = [1,3,2]
输出:[2,3,1]
思路:
遍历一遍链表,用栈存储,然后再用栈弹出存进数组
package listNode;
import java.util.Stack;
public class ReversePrint {
public int[] reversePrint(ListNode head){
Stack<Integer> stack = new Stack<>();
while(head != null){
stack.push(head.val);
head = head.next;
}
int[] res = new int[stack.size()];
for(int i = 0; i < res.length;i++){
res[i] = stack.pop();
}
return res;
}
public static void main(String[] args) {
ListNode head = new ListNode(1);
head.next = new ListNode(2);
head.next.next = new ListNode(3);
head.next.next.next = new ListNode(4);
head.next.next.next.next = new ListNode(5);
ReversePrint test = new ReversePrint();
int[] res = test.reversePrint(head);
for(int i:res){
System.out.print(i + " ");
}
}
}
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