注意二分初始值
https://www.cnblogs.com/NaVi-Awson/p/7252243.html
#include<cstdio>
#include<algorithm>
using namespace std;
const int N=50000+5,M=100000+5;
int n,m,need;
struct edge{int x,y,z,cor;}a[M]; int mid,sum;
bool cmp(edge p,edge q)
{if(p.z+p.cor*mid==q.z+q.cor*mid) return p.cor<q.cor;
return p.z+p.cor*mid<q.z+q.cor*mid;
}
int f[N];
int find(int x)
{if(f[x]==x) return x;
return f[x]=find(f[x]);
}
inline bool check()
{for(int i=1;i<=n;i++) f[i]=i;
sort(a+1,a+m+1,cmp);
int cnt=0,link=0; sum=0;
for(int i=1;i<=m;i++)
{int r1=find(a[i].x),r2=find(a[i].y);
if(r1==r2) continue;
f[r1]=r2; link++;
sum+=a[i].z; cnt+=a[i].cor;
if(link==n-1) break;
}
return cnt>=need;
}
int main()
{
scanf("%d%d%d",&n,&m,&need);
for(int i=1;i<=m;i++)
{scanf("%d%d%d%d",&a[i].x,&a[i].y,&a[i].z,&a[i].cor);
a[i].x++; a[i].y++; a[i].cor=1-a[i].cor;
}
int l=-105,r=105,ans=0;
while(l<=r)
{mid=(l+r)/2;
if(check()) ans=sum,l=mid+1;
else r=mid-1;
}
printf("%d",ans);
return 0;
}
转载于:https://www.cnblogs.com/YuXiaoze/p/10679528.html