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题目描述：

用户输入一个算术运算的式子，运算包括了+、-、*、/、%，首先输出该式子，如果运算符不在这5种操作内，输出运算符错误的信息；如果式子是正确的，输出式子正确的相应信息；如果式子是错误的，输出式子错误的相应信息。例如：

输入：1+2=3

输出：1+2=3 correct

输入：2/3=8

输出：2/3=8 wrong

输入：6&7=12

输出：6&7=12 error op

输入要求：

一个算术式子

输出要求：

该式子以及对错信息

#include<iostream>
using namespace std;

int main() {
	int a, b, c;
	char d, e;
	cin >> a >> d >> b >> e >> c;
	if (d == '+' || d == '-' || d == '*' || d == '/' || d == '%') {
		switch (d) {//利用选择结构来判断符号
		case('+'):if (a + b == c) {
			cout << a << d << b << e << c << " correct" << endl;
		}
				 else cout << a << d << b << e << c << " wrong" << endl;
			break;
		case('-'):if (a - b == c) {
			cout << a << d << b << e << c << " correct" << endl;
		}
				 else cout << a << d << b << e << c << " wrong" << endl;
			break;
		case('*'):if (a * b == c) {
			cout << a << d << b << e << c << " correct" << endl;
		}
				 else cout << a << d << b << e << c << " wrong" << endl;
			break;
		case('/'):if (a / b == c) {
			cout << a << d << b << e << c << " correct" << endl;
		}
				 else cout << a << d << b << e << c << " wrong" << endl;
			break;
		case('%'):if (a % b == c) {
			cout << a << d << b << e << c << " correct" << endl;
		}
				 else cout << a << d << b << e << c << " wrong" << endl;
			break;
		}
	}
	else cout << a << d << b << e << c << " error op" << endl;
	return 0;
}

如有更简单的方法请赐教~~