文章目录
一、wapper介绍
Wrapper : 条件构造抽象类,最顶端父类
AbstractWrapper : 用于查询条件封装,生成 sql 的 where 条件
QueryWrapper : Entity 对象封装操作类,不是用lambda语法
UpdateWrapper : Update 条件封装,用于Entity对象更新操作
AbstractLambdaWrapper : Lambda 语法使用 Wrapper统一处理解析 lambda 获取 column。
LambdaQueryWrapper :看名称也能明白就是用于Lambda语法使用的查询Wrapper
LambdaUpdateWrapper : Lambda 更新封装Wrapper
二、AbstractWrapper
注意:以下条件构造器的方法入参中的 column 均表示数据库字段
1、ge(大于等于)、gt(大于)、le(小于等于)、lt(小于)、isNull、isNotNull
例如:查询年龄在20~80之间的用户
//查询大于80岁的用户
@Test
public void testSelectDemo1(){
//构造条件
QueryWrapper<User> wrapper = new QueryWrapper<>();
//age>20 and age<80
wrapper.gt("age",20).lt("age",80);
List<User> users = userMapper.selectList(wrapper);
System.out.println(users);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,version,deleted FROM user WHERE deleted=0 AND age > ? AND age < ?
2、eq、ne
注意:
seletOne返回的是一条实体记录,当出现多条时会报错
@Test
public void testSelectDemo2(){
QueryWrapper<User> wrapper = new QueryWrapper<>();
//用户名为东方不败
wrapper.eq("name","东方不败").ne("age",28);
List<User> users = userMapper.selectList(wrapper);
System.out.println(users);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,version,deleted FROM user WHERE deleted=0 AND name = ? AND age <> ?
3、allEq
@Test
public void testSelectList() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
Map<String, Object> map = new HashMap<>();
map.put("id", 10);
map.put("name", "东方不败");
map.put("age", 50);
queryWrapper.allEq(map);
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND name = ? AND id = ? AND age = ?
4、between、notBetween
包含大小边界
@Test
public void testSelectCount() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.between("age", 10, 40);
Integer count = userMapper.selectCount(queryWrapper);
System.out.println(count);
}
SQL语句:
SELECT COUNT(1) FROM user WHERE deleted=0 AND age BETWEEN ? AND ?
5、like(%xx%)、notLike、likeLeft(%xx)、likeRight(xx%)
selectMaps返回Map集合列表
@Test
public void testSelectMaps() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper
.notLike("name", "武大郎")
.likeRight("email", "xxx@qq.com");
List<Map<String, Object>> maps = userMapper.selectMaps(queryWrapper);//返回值是Map列表
maps.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND name NOT LIKE ? AND email LIKE ?
6、in、notIn、inSql、notinSql、exists、notExists
in、notIn:
- notIn(“age”,{1,2,3})—>age not in (1,2,3)
- notIn(“age”, 1, 2, 3)—>age not in (1,2,3)
inSql、notinSql:可以实现子查询
-
例: inSql(“age”, “1,2,3,4,5,6”)
--->
age in (1,2,3,4,5,6) - 例: inSql(“id”, “select id from table where id < 3”)—>id in (select id from table where id < 3)
@Test
public void testSelectObjs() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
//queryWrapper.in("id", 1, 2, 3);
queryWrapper.inSql("id", "select id from user where id < 3");
List<Object> objects = userMapper.selectObjs(queryWrapper);//返回值是Object列表
objects.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND id IN (select id from user where id < 3)
7、or、and
注意:这里使用的是 UpdateWrapper
不调用
or
则默认为使用
and
连
@Test
public void testUpdate1() {
//修改值
User user = new User();
user.setAge(99);
user.setName("Andy");
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")
.or()
.between("age", 20, 30);
int result = userMapper.update(user, userUpdateWrapper);
System.out.println(result);
}
SQL语句:
UPDATE user SET name=?, age=?, update_time=? WHERE deleted=0 AND name LIKE ? OR age BETWEEN ? AND ?
8、嵌套or、嵌套and
这里使用了lambda表达式
,or中的表达式最后翻译成sql时会被加上圆括号
@Test
public void testUpdate2() {
//修改值
User user = new User();
user.setAge(99);
user.setName("Andy");
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")
.or(i -> i.eq("name", "李白").ne("age", 20));
int result = userMapper.update(user, userUpdateWrapper);
System.out.println(result);
}
SQL语句:
UPDATE user SET name=?, age=?, update_time=?
WHERE deleted=0 AND name LIKE ?
OR ( name = ? AND age <> ? )
9、orderBy、orderByDesc、orderByAsc
@Test
public void testSelectListOrderBy() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.orderByDesc("id");
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 ORDER BY id DESC
10、last
直接拼接到 sql 的最后
注意:
只能调用一次,多次调用以最后一次为准 有sql注入的风险,请谨慎使用
@Test
public void testSelectListLast() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.last("limit 1");
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 limit 1
11、指定要查询的列
@Test
public void testSelectListColumn() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.select("id", "name", "age");
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SQL语句:
SELECT id,name,age FROM user WHERE deleted=0
12、set、setSql
最终的sql会合并 user.setAge(),以及 userUpdateWrapper.set() 和 setSql() 中 的字段
@Test
public void testUpdateSet() {
//修改值
User user = new User();
user.setAge(99);
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")//where语句后的条件
.set("name", "老李头")//除了可以查询还可以使用set设置修改的字段
.setSql(" email = '123@qq.com'");//可以有子查询
int result = userMapper.update(user, userUpdateWrapper);
}
SQL语句:
UPDATE user SET age=?, update_time=?, name=?, email = '123@qq.com' WHERE deleted=0 AND name LIKE ?
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