Linux循环链表队列,使用linux中标准的queue.h头文件插件链表,队列,循环队列

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  • Post category:linux


#include

#include #include int test_list()

{

LIST_HEAD(listhead, entry) head;

struct listhead *headp;                 /* List head. */

struct entry {

char name[64];

char sexy[8];

int age;

LIST_ENTRY(entry) entries;          /* List. */

} *n1, *n2, *np;

LIST_INIT(&head);                       /* Initialize the list. */

n1 = malloc(sizeof(struct entry));      /* Insert at the head. */

strcpy(n1->name,”Tom”);

strcpy(n1->sexy,”boy”);

n1->age = 25;

LIST_INSERT_HEAD(&head, n1, entries);

n2 = malloc(sizeof(struct entry));      /* Insert after. */

strcpy(n2->name,”Hameimei”);

strcpy(n2->sexy,”girl”);

n2->age = 23;

LIST_INSERT_AFTER(n1, n2, entries);

/* Forward traversal. */

for (np = head.lh_first; np != NULL; np = np->entries.le_next)

{

printf(“%s %s %d\n”,np->name,np->sexy,np->age);

}

while (head.lh_first != NULL)           /* Delete. */

LIST_REMOVE(head.lh_first, entries);

return 0;

}

int test_queue()

{

TAILQ_HEAD(tailhead, entry) head;

struct tailhead *headp;                 /* Tail queue head. */

struct entry {

char name[64];

char sexy[8];

int age;

TAILQ_ENTRY(entry) entries;         /* Tail queue. */

} *n1, *n2, *n3,*np;

TAILQ_INIT(&head);                      /* Initialize the queue. */

n1 = malloc(sizeof(struct entry));      /* Insert at the head. */

strcpy(n1->name,”Tom”);

strcpy(n1->sexy,”boy”);

n1->age = 25;

TAILQ_INSERT_HEAD(&head, n1, entries);

n2 = malloc(sizeof(struct entry));      /* Insert at the tail. */

strcpy(n2->name,”Jim”);

strcpy(n2->sexy,”boy”);

n2->age = 24;

TAILQ_INSERT_TAIL(&head, n2, entries);

n3 = malloc(sizeof(struct entry));      /* Insert after. */

strcpy(n3->name,”Hameimei”);

strcpy(n3->sexy,”girl”);

n3->age = 22;

TAILQ_INSERT_AFTER(&head, n1, n3, entries);

/* Forward traversal. */

for (np = head.tqh_first; np != NULL; np = np->entries.tqe_next)

printf(“%s %s %d\n”,np->name,np->sexy,np->age);

/* Delete. */

while (head.tqh_first != NULL)

TAILQ_REMOVE(&head, head.tqh_first, entries);

return 0;

}

int test_circular()

{

CIRCLEQ_HEAD(circleq, entry) head;

struct circleq *headp;              /* Circular queue head. */

struct entry {

char name[64];

char sexy[8];

int age;

CIRCLEQ_ENTRY(entry) entries;   /* Circular queue. */

} *n1, *n2, *n3,*n4,*np;

CIRCLEQ_INIT(&head);                /* Initialize the circular queue. */

n1 = malloc(sizeof(struct entry));  /* Insert at the head. */

strcpy(n1->name,”Tom”);

strcpy(n1->sexy,”boy”);

n1->age = 25;

CIRCLEQ_INSERT_HEAD(&head, n1, entries);

n2 = malloc(sizeof(struct entry));  /* Insert at the tail. */

strcpy(n2->name,”Jim”);

strcpy(n2->sexy,”boy”);

n2->age = 24;

CIRCLEQ_INSERT_TAIL(&head, n2, entries);

n3 = malloc(sizeof(struct entry));  /* Insert after. */

strcpy(n3->name,”Hameimei”);

strcpy(n3->sexy,”girl”);

n3->age = 22;

CIRCLEQ_INSERT_AFTER(&head, n1, n3, entries);

n4 = malloc(sizeof(struct entry));  /* Insert before. */

strcpy(n4->name,”Lilei”);

strcpy(n4->sexy,”boy”);

n4->age = 30;

CIRCLEQ_INSERT_BEFORE(&head, n1, n4, entries);

/* Forward traversal. */

printf(“Forward traversal.\n”);

for (np = head.cqh_first; np != (void *)&head;

np = np->entries.cqe_next)

printf(“%s %s %d\n”,np->name,np->sexy,np->age);

/* Reverse traversal. */

printf(“Reverse traversal.\n”);

for (np = head.cqh_last; np != (void *)&head; np = np->entries.cqe_prev)

printf(“%s %s %d\n”,np->name,np->sexy,np->age);

/* Delete. */

while (head.cqh_first != (void *)&head)

CIRCLEQ_REMOVE(&head, head.cqh_first, entries);

}

int main(int argc, char *argv[])

{

printf(“Test list…\n”);

test_list();

printf(“________________________\n”);

printf(“Test queue…\n”);

test_queue();

printf(“________________________\n”);

printf(“Test circular…\n”);

test_circular();

printf(“________________________\n”);

return 0;

}

Test list…

Tom boy 25

Hameimei girl 23

________________________

Test queue…

Tom boy 25

Hameimei girl 22

Jim boy 24

________________________

Test circular…

Forward traversal.

Lilei boy 30

Tom boy 25

Hameimei girl 22

Jim boy 24

Reverse traversal.

Jim boy 24

Hameimei girl 22

Tom boy 25

Lilei boy 30

________________________