如果您从URL urlObject = new URL(url)之类的字符串创建新的URL对象,然后执行urlObject.getQuery()和urlObject.getPath()将其拆分为右,将Query Params解析为List或Map或做某事并做一些事情：
编辑：我刚刚发现HttpClient库有一个URLEncodedUtils.parse()方法,您可以使用下面提供的代码轻松使用它.我会编辑它以适应,但是未经测试.
使用Apache HttpClient,它将类似于：
URI urlObject = new URI(url,”UTF-8″);
HttpClient httpclient = new DefaultHttpClient();
List formparams = URLEncodedUtils.parse(urlObject,”UTF-8″);
UrlEncodedFormEntity entity;
entity = new UrlEncodedFormEntity(formparams);
HttpPost httppost = new HttpPost(urlObject.getPath());
httppost.setEntity(entity);
httppost.addHeader(“Content-Type”,”application/x-www-form-urlencoded”);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity2 = response.getEntity();
使用Java URLConnection,它将类似于：
// Iterate over query params from urlObject.getQuery() like
while(en.hasMoreElements()){
String paramName = (String)en.nextElement(); // Iterator over yourListOfKeys
String paramValue = yourMapOfValues.get(paramName); // replace yourMapOfNameValues
str = str + “&” + paramName + “=” + URLEncoder.encode(paramValue);
}
try{
URL u = new URL(urlObject.getPath()); //here’s the url path from your urlObject
URLConnection uc = u.openConnection();
uc.setDoOutput(true);
uc.setRequestProperty(“Content-Type”,”application/x-www-form-urlencoded”);
PrintWriter pw = new PrintWriter(uc.getOutputStream());
pw.println(str);
pw.close();
BufferedReader in = new BufferedReader(new
InputStreamReader(uc.getInputStream()));
String res = in.readLine();
in.close();
// …
}