子查询按照结果返回情况分为:单行子查询,多行子查询
单行子查询操作符:
多行子查询:
**
exists,not exists关键字
如果在子查询不存在满足条件的行:
返回false,继续在子查询中查找
如果在子查询中存在满足条件的行:
不在子查询中继续寻找,返回true
not exists关键字表示如果不存在某种条件,返回true,否则返回false
practise:
1.查询和Zlotkey相同部门的员工姓名和工资
SELECT last_name, salary
FROM employees
WHERE department_id = (
SELECT department_id
FROM employees
WHERE last_name = ‘Zlotkey’
)
2.查询工资比公司平均工资高的员工的员工号,姓名和工资
SELECT employee_id, last_name, salary
FROM employees
WHERE salary > (
SELECT AVG(salary)
FROM employees
)
3.选择工资大于所有JOB_ID = ‘SA_MAN’的员工的工资的员工的last_name,job_id, salary
SELECT last_name,job_id,salary
FROM employees
WHERE salary > ALL (
SELECT salary
FROM employees
WHERE job_id = ‘SA_MAN’
);
4.查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名
SELECT employee_id, last_name
FROM employees
WHERE department_id = ANY(
SELECT DISTINCT department_id
FROM employees
WHERE last_name LIKE ‘%u%’
)
5.查询在部门的location_id为1700的部门工作的员工的员工号
SELECT employee_id
FROM employees
WHERE department_id IN (
SELECT department_id
FROM departments
WHERE location_id = 1700
)
6.查询管理者是King的员工姓名和工资
SELECT last_name, salary
FROM employees
WHERE manager_id IN (
SELECT employee_id
FROM employees
WHERE last_name = ‘King’
)
-
查询工资最低的员工信息: last_name, salary
SELECT last_name,salary
FROM employees
WHERE salary = (
SELECT MIN(salary)
FROM employees
); -
查询平均工资最低的部门信息
SELECT *
FROM departments
WHERE department_id = (
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary) = (
SELECT MIN(dept_avgsal)
FROM (
SELECT AVG(salary) dept_avgsal
FROM employees
GROUP BY department_id
) avg_sal
)
);
9.查询平均工资最低的部门信息和该部门的平均工资(相关子查询)
SELECT d.*,(SELECT AVG(salary) FROM employees WHERE department_id = d.department_id)
avg_sal
FROM departments d
WHERE department_id = (
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary) = (
SELECT MIN(dept_avgsal)
FROM (
SELECT AVG(salary) dept_avgsal
FROM employees
GROUP BY department_id
) avg_sal
)
);
-
查询平均工资最高的 job 信息
SELECT *
FROM jobs
WHERE job_id = (
SELECT job_id
FROM employees
GROUP BY job_id
HAVING AVG(salary) = (
SELECT MAX(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY job_id
) job_avgsal
)
); -
查询平均工资高于公司平均工资的部门有哪些?
SELECT department_id
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING AVG(salary) > (
SELECT AVG(salary)
FROM employees
); -
查询出公司中所有 manager 的详细信息.
SELECT employee_id,last_name,salary
FROM employees
WHERE employee_id IN (
SELECT DISTINCT manager_id
FROM employees
); -
各个部门中 最高工资中最低的那个部门的 最低工资是多少?
SELECT MIN(salary)
FROM employees
WHERE department_id = (
SELECT department_id
FROM employees
GROUP BY department_id
HAVING MAX(salary) = (
SELECT MIN(max_sal)
FROM (
SELECT MAX(salary) max_sal
FROM employees
GROUP BY department_id) dept_max_sal
)
);
SELECT *
FROM employees
WHERE department_id = 10; -
查询平均工资最高的部门的 manager 的详细信息: last_name,department_id, email, salary
SELECT employee_id,last_name, department_id, email, salary
FROM employees
WHERE employee_id IN (
SELECT DISTINCT manager_id
FROM employees
WHERE department_id = (
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary) = (
SELECT MAX(avg_sal)
FROM( -
查询部门的部门号,其中不包括job_id是”ST_CLERK”的部门号
SELECT department_id
FROM departments d
WHERE department_id NOT IN (
SELECT DISTINCT department_id
FROM employees
WHERE job_id = ‘ST_CLERK’
); -
选择所有没有管理者的员工的last_name
SELECT last_name
FROM employees e1
WHERE NOT EXISTS (
SELECT *
FROM employees e2
WHERE e1.manager_id = e2.employee_id
);
17.查询员工号、姓名、雇用时间、工资,其中员工的管理者为 ‘De Haan’
SELECT employee_id, last_name, hire_date, salary
FROM employees
WHERE manager_id = (
SELECT employee_id
FROM employees
WHERE last_name = ‘De Haan’
)
18.查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资(难)
SELECT employee_id,last_name,salary
FROM employees e1
WHERE salary > (
SELECT AVG(salary)
FROM employees e2
WHERE e2.department_id = e1.department_id
);
19.查询每个部门下的部门人数大于 5 的部门名称
SELECT department_name,department_id
FROM departments d
WHERE 5 < (
SELECT COUNT(*)
FROM employees e
WHERE d.department_id
= e.department_id
);
20.查询每个国家下的部门个数大于 2 的国家编号
SELECT country_id
FROM locations l
WHERE 2 < (
SELECT COUNT(*)
FROM departments d
WHERE l.location_id
= d.location_id
);